In Chapter 4-4, you will have to know binary coding to pass the room.

When you pres the different buttons on each side of the room, the wall will extend a blade showing you the clues to pass the room.

Get all Doors & Room Games from the App Store.

Doors&Rooms

Doors&Rooms 2

Doors&Rooms 3

Doors&Rooms Zero

Doors&Rooms

Doors&Rooms 2

Doors&Rooms 3

Doors&Rooms Zero

Based on binary code, you have the following.

0001 = 1

0010 = 2

0011 = 3

0100 = 4

0101 = 5

0110 = 6

0111 = 7

1000 = 8

Now when you press the stone blocks along the walls, you will see metal plates showing its numbers. These numbers are

1000 = 8

0101 = 5

0011 = 3

0100 = 4

With this, you will be able to escape from the room.

**Speed Pass Note**

You can instantly pass the room by pressing the codes 8534. It does not have to be that order.

how could you get that??

O.m.g i havent studied binary code in years! How could someone have gotten that!?

binary code? interesting …

the clue to use binary code is 1, 2 4, 8 which is 2 raised to power of x or doubling every number then when you have 0’s and 1’s you should make that connection

I used matrices and solve this…. hmm… lucky guess i think…..

I did not know about the binary, I just used the room number 8421 and used the code as a marker/reference. I.E 8421 with 1000 = 8; 8421 with 0101 means i add 4 and 1 getting 5 and so on going clockwise. It must have been a lucky guess for me.

I think thats the good way to found it

That’s exactly the way binary works

Are you kidding me.. The binary code.. What the… Ridiculous..

When I saw the numbers on the blade I thought of binary code, then I thought there’s no way a game would put something that no average human would think of… well I couldn’t find the answer and came here, it was in fact binary .-.